A chiropractor applies a thrust to the spinous process of T6. The magnitude is 400 N and it is applied 90 degrees to the y-axis. While this occurs the superior disc applies a force to the T6 body of 615 N, 75 degrees to the x-axis. The inferior disc applies a force to the T6 body of 620 N, 70 degrees to the x-axis. Finally, the interspinous ligament applies a force of 32 N, 60 degrees to the y-axis. Determine the resultant force acting on the T6 vertebra, and the direction with respect to the x-axis. Note: Use only two decimal points(adsbygoogle = window.adsbygoogle || []).push({});

In question chiropractor applies a thrust to spinous process t6 which is in the back.

attempt 1

(68.88x68.88+ 14.09x14.09) 1/2= 70.31n

attempt: 2

400nsin 0+ 615 sin 75+ -620sin 70+- 32ncos 60= -2.25

400cos0+ -615 cos 75+ 620 cos 70+ -32n sin 60= -27.04

(2.25x2.25+ 27.04x27.04) 1/2 = 25.04N

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# Homework Help: Resultant force

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