Reversible adiabatic expansion/compression equal to zero

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SUMMARY

The change in entropy for a reversible adiabatic expansion or compression is zero because there is no heat transfer and no entropy is created during the process. In contrast, irreversible adiabatic processes generate entropy due to mechanisms like turbulence, which prevent the system from returning to its original state. The adiabatic condition ensures that no entropy enters or leaves the system, maintaining constant entropy within the system. This distinction is crucial for understanding thermodynamic processes and their implications on entropy.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically the laws of thermodynamics.
  • Familiarity with the concept of entropy as a state function.
  • Knowledge of adiabatic processes and their characteristics.
  • Basic grasp of reversible versus irreversible processes in thermodynamics.
NEXT STEPS
  • Explore the concept of entropy generation in irreversible processes.
  • Study the implications of the second law of thermodynamics on real-world systems.
  • Investigate the mathematical formulation of reversible processes in thermodynamics.
  • Learn about the role of temperature gradients in entropy changes during heating processes.
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Students of thermodynamics, physicists, and engineers interested in understanding the principles of entropy and its behavior in reversible and irreversible processes.

a9211l
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So, I am looking a question about adiabatic expansions and the associated entropy changed.

Why exactly is the change in entropy for a reversible adiabatic expansion/compression equal to zero? The book says its because there is no heat transfer, but for irreversible adiabatic processes, there is also no heat transfer. So no matter what, shouldn't the entropy of the surroundings for an adiabatic process be zero? In terms of the system, since entropy is a state function, why would it matter whether its reversible or irreversible?
 
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Hi a9211l, these are great questions. First, the adiabatic requirement just ensures that no entropy enters or leaves the system by way of heating. However, in an irreversible process we create entropy. Or it might be better to say it in reverse: when we create entropy through a mechanism like turbulence, the process is irreversible. The system will never spontaneously go back to its orginal state, because entropy always tends to increase in a closed system.

Thus, one answer to your question is that no entropy enters or leaves the system (work is a transfer of energy without an accompanying transfer of entropy), and no entropy is created. Therefore, the system entropy is constant.

So what would create entropy? Entropy is created whenever a process occurs due to a gradient (in charge, temperature, material concentration, etc.). This is how all real process occur: irreversibly. But we might imagine making the gradient very small to reduce the creation of entropy. This idea taken to its limit gives us the reversible process, an idealization in which we imagine the gradient to be exactly zero.

Is this helpful?
 
yes, that is very helpful. it made sense to me theoretically (idk if that's the right term...), but just needed that physical explanation.
 
A second question then, if I do a constant pressure heating of some non-adiabatic system, that still changes the entropy in the surroundings, correct?
 
Yes, heating a system increases the entropy of the system, reduces the entropy of the surroundings, and creates entropy at the interface due to the temperature gradient.
 

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