Rewrite equation (rationalize denominator)

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AI Thread Summary
The discussion focuses on a College Algebra problem involving the rationalization of a denominator in an equation. The original equation is M = Mo / √(1 - v²/c²), which needs to be transformed into M = Mo c √(c² - v²) / (c² - v²). The participant initially struggled with the rationalization process but identified a mistake involving an incorrect "+" sign in their calculations. After receiving feedback, they realized the need to split c² and correctly apply the rationalization technique. The conversation highlights the importance of careful verification in mathematical problem-solving.
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Homework Statement



I just started on College Algebra (online) and completed the homework for the first chapter.
There is one question which is not part of the homework, but it looks interesting so I gave it a try, but I get stuck at some point and would like some pointers of how to solve it

The questions is

Show that the equation
M = \frac {M_o} {\sqrt{1 - \frac{v^2}{c^2}}}


can be written in the form
M = \frac {M_oc \sqrt{c^2-v^2} } {c^2-v^2}

Homework Equations




The Attempt at a Solution



I tried to rationalize the denominator and got to

M = \frac {M_oc^2 \sqrt{1 + \frac{v^2}{c^2}} } {c^2-v^2}

But I can't see how to turn

M_oc^2 \sqrt{1 + \frac{v^2}{c^2}}

into

M_oc \sqrt{c^2-v^2}


Any help is appreciated.


Jesper
 
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Hi Jesper! :smile:

(have a square-root: √ :wink:)
jkristia said:
M = M0c2 sqrt(1 + v2/c2) / (c2 - v2)

erm :redface: … where did that "+" come from? :wink:
 
Hi Tim,
Just spend the last 1/2 hour trying to enter the equation using Latex.

argh ... found my mistake, thank you for pointint it out :)

edit - actually, that was REALLY embarrassing, next time I will triple check before asking
 
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jkristia said:
I just started on Colage Algebra (online)
That would be College Algebra.

Collage is a word in English, but it doesn't have anything to do with education. Colage is not a word in English. College is the word you want.
 
>>That would be College Algebra.

yes of course :)
 
Try splitting your c^2 that is outside of the square root, into c*c and see where you can go from there =)
 
Thanks your your help, but I found the problem as soon as tiny-tim pointed out the '+'.
This was one of my typical 'duh' mistakes. I had been doing exercises where the denominator was of form

(sqrt(a) - b)

so I had been rationalizing by multiplying with (sqrt(a) + b) in the denominator, and I did the same with this one, so that is where the '+' came from.

Of course in this case I just need to square the squareroot, and once I realized that it was straight forward.

Jesper
 
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