Rewriting a symbolic Summation

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user3 said:
Consider this Summation: ∑cos^2 (∏*n / 4) limits: -N to N

when I type that on wolframAlpha I get the following:

http://www.wolframalpha.com/input/?i=summation+(1++cos(pi+n+/+2))+from+-N+to+N


I have no Idea how it was performed though.


how Can I transform this from summation form to this other algebraic form?

Pick a value for N, and expand the summation.
Pick a different value for N, and expand the summation.
After you do this a few times, maybe you can discover a pattern.
 
user3 said:
Consider this Summation: ∑cos^2 (∏*n / 4) limits: -N to N

when I type that on wolframAlpha I get the following:

http://www.wolframalpha.com/input/?i=summation+(1++cos(pi+n+/+2))+from+-N+to+N


I have no Idea how it was performed though.


how Can I transform this from summation form to this other algebraic form?

Standard method:
\sum_{n=a}^{b} \cos(nw) = \frac{1}{2}\sum_{n=a}^{b} \left(e^{inw} + e^{-inw} \right)
This is a sum of two geometric series ##\sum r^n## with ##r = e^{iw}## and ##r = e^{-iw}##.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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