Riding With a Particle: Measuring Its Lifetime

AI Thread Summary
A particle moving at 0.996c has a measured lifetime of 3.00 x 10^-8 seconds from a stationary observer's perspective. To find the lifetime for someone traveling with the particle, the proper time formula t = t(0) / √(1 - v^2/c^2) is used. The initial attempt yielded an incorrect result of 3 x 10^-9 seconds. It is suggested to carry more significant figures in calculations to improve accuracy. The discussion emphasizes the importance of proper time calculations in relativistic contexts.
cshelbythec
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A particle lives for a short time before breaking apart into other particles. Suppose it is moving at a speed of 0.996c, and an observer who is stationary in a laboratory measures the particle's lifetime to be 3.00 10-8 s.
What is the lifetime according to a hypothetical person who is riding along with the particle?




The Attempt at a Solution


I tried
t=t(0)/(1-v2/c2)^1/2
where t=3.00 10-8s and I'm finding t(0) proper.
my answer is 3 10-9 which is wrong. what am I doing wrong?
 
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cshelbythec said:
A particle lives for a short time before breaking apart into other particles. Suppose it is moving at a speed of 0.996c, and an observer who is stationary in a laboratory measures the particle's lifetime to be 3.00 10-8 s.
What is the lifetime according to a hypothetical person who is riding along with the particle?




The Attempt at a Solution


I tried
t=t(0)/(1-v2/c2)^1/2
where t=3.00 10-8s and I'm finding t(0) proper.
my answer is 3 10-9 which is wrong. what am I doing wrong?
i have forgotten this stuff, but try multiplying it if dividing doesn't work
 
cshelbythec said:
my answer is 3 10-9 which is wrong. what am I doing wrong?
I suggest carrying more significant figures in your answer.
 
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