Riemann Integrability of Composition

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Homework Statement


Let ψ(x) = x sin 1/x for 0 < x ≤ 1 and ψ(0) = 0.
(a) If f : [-1,1] → ℝ is Riemann integrable, prove that f \circ ψ is Riemann integrable.
(b) What happens for ψ*(x) = √x sin 1/x?


Homework Equations


I've proven that if ψ : [c,d] → [a,b] is continuous and for every set of measure zero Z \subset [a,b], ψ^{\text{pre}}(Z) is a set of measure zero in [c,d], then if f is Riemann integrable, f \circ ψ is Riemann integrable. However, this doesn't apply well in this situation. What can I do? I have a hunch that both f \circ ψ and f \circ ψ* are Riemann integrable.


The Attempt at a Solution

 
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Any suggestions?
 
What do you know about Riemann integration?? What theorems could come in handy?
For example, do you know that a function is Riemann integrable iff the set of discontinuities has measure 0?
 
SammyS: My apologies, it was not twenty-four hours.

Micromass: I am aware of that theorem, and in fact used it to prove the theorem in the original post. The problem is that I do not know how to show that the set of discontinuities of f \circ \psi are of measure 0. Clearly it is discontinuous at a point u iff f is discontinuous at \psi(u), but I don't know where to go from here.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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