Rigid Pendulum g derivation equation

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SUMMARY

The discussion focuses on deriving the equation for gravitational acceleration "g" in terms of measurable quantities such as M, Mbar, h, L, b, T, To, and Tbar. The key equations utilized include T = 2π(I / Mgh)^(0.5), (Io / Ibar) = (To / Tbar)^(2), Ibar = (Mbar / 12)(L^2 + b^2), and I = Io + Mh^2. The final derived equation for "g" is g = [({[(To / Tbar)^(2)][(Mbar / 12)(L^2 + b^2)] + Mh^2}*4π^2) / (T^2)] / (Mh), which incorporates all relevant variables and constants.

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Rigid Pendulum "g" derivation equation

Homework Statement



Determine the general equation for "g" in terms of measurable quantities(M, Mbar, h, L, b, T, To, Tbar) from the following equations: (refer below)


Homework Equations



(1) T = 2pi(I / Mgh)^(0.5)

(2) (Io / Ibar) = (To / Tbar)^(2)

(3) Ibar = (Mbar / 12)(L^2 + b^2)

(4) I = Io + Mh^2



The Attempt at a Solution



- Alright first i re - arranged eqn. (1) so that g = [ (I*4pi^2) / (T^2)] / (Mh)

- Then i re - arranged eqn. (2) so that Io = [(To / Tbar)^(2)](Ibar)

- I then used eqn (3) and subbed it into the new equation (2)

Io = [(To / Tbar)^(2)][(Mbar / 12)(L^2 + b^2)] (5)

- I then subbed in our newly formed eqn (5) into eqn (4)

I = [(To / Tbar)^(2)][(Mbar / 12)(L^2 + b^2)] + Mh^2 (6)

- Now i sub eqn (6) back into our re arranged equation for g

g = [({[(To / Tbar)^(2)][(Mbar / 12)(L^2 + b^2)] + Mh^2}*4pi^2) / (T^2)] / (Mh)

and that's my final answer
 
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