RMS Speed of Helium Atom at 2000K: An Overview

AI Thread Summary
The discussion focuses on calculating the root mean square (rms) speed of a helium atom at a temperature of 2000°C. Participants clarify the need for unit conversion to meters per second (m/s) for accurate results. The conversation includes a reference to a HyperPhysics link that provides relevant information on kinetic theory and temperature conversions. The initial query lacks clarity, prompting further questions about the specific calculations required. Overall, the thread emphasizes the importance of understanding temperature units in relation to atomic speed calculations.
courtneylane8
Messages
6
Reaction score
0
What is the rms speed of helium atom at 2000?
 
Physics news on Phys.org
Welcome to PF.

What units are you thinking it is?

Where would you think to start?
 
I want to convert to m/s
 
courtneylane8 said:
I want to convert to m/s

Convert what to m/s?

What is 2000?
 
sorry! its celcius
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top