Rocket ascending in Earth's gravity

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The discussion focuses on determining the velocity of a rocket ascending in Earth's gravity while accounting for mass ejection and air resistance. The rocket's mass decreases at a rate defined by dm/dt = -γm, and it experiences a retarding force due to air resistance proportional to its velocity. The derived velocity function is v(t) = (1/b)e^((-uγ/b)t) - (g/b), with terminal velocity given by (γu - g)/b. A key challenge noted is the ambiguity surrounding the constant γ, as no initial condition is provided to specify its value. Ultimately, the solution requires expressing results in terms of γ due to its constant nature.
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Homework Statement


A rocket ascends from rest in Earth's gravitational field, by ejecting exhaust with constant speed u. Assume that the rate at which mass is expelled is given by dm/dt = −γm where m is the instantaneous mass of the rocket and γ is a constant; and that the rocket is retarded by air resistance with a force mbv where b is a constant.
Determine the velocity of the rocket as a function of time. Here is a hint: The terminal velocity is ( γu−g )/b.

Calculate the time when the velocity is one-half of the terminal velocity.
Data: u = 31.9 m/s; b = 1.2 s−1.


Homework Equations


dp/dt=F=m(dv/dt)



The Attempt at a Solution


I get dv=-udm-(g+bv)dt; dm=-γm
so dv=uγ-(g+bv)dt

solving for v:
v(t)=(1/b)e^((-uγ/b)t)-(g/b)

the problem I am running into is what is gamma, because I have no inital condition to apply, and I'm fairly sure the solution to the diff eq is correct.
 
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gamma is just a constant, it doesn't really matter what it is, your answers will probably just have to be expressed in terms of it.
 
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