Rocket expelling fuel velocity relative to earth

AI Thread Summary
The discussion revolves around calculating the speed of a rocket relative to Earth after its mass is halved due to fuel expulsion. The initial speed of the rocket is 3.0 × 10^3 m/s, with fuel ejected at 5.0 × 10^3 m/s relative to the rocket. Participants emphasize the need to apply momentum conservation principles and select the Earth as the reference frame for accurate calculations. The complexity arises from the changing speed of exhaust in an inertial frame as the rocket accelerates. Understanding and applying the Tsiolkovsky rocket equation is essential for solving the problem effectively.
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Homework Statement


A rocket moving in space, far from all other objects, has a speed of 3.0 × 103 ms−1 relative to the Earth. Its engines are turned on, and fuel is ejected in a direction opposite to the rocket’s motion at a speed of 5.0 × 103 ms−1 relative to the rocket. What is the speed of the rocket relative to the Earth once the rocket’s mass is reduced to half its mass before ignition?

Homework Equations


vfuel = v - vex

The Attempt at a Solution


Quite unsure as to how to attempt this. How do I found vex in order to find v? It has something to do with the mass but I'm not sure how to relate it.

This question is only worth 2 marks so I don't think I'm expected to show much. Thank you.
 
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You have to use momentum conservation but you need to pick a referance frame.Pick Earth referance frame calculate velocities to Earth,then use momentum conservation
 
ArmanCham said:
You have to use momentum conservation but you need to pick a referance frame.Pick Earth referance frame calculate velocities to Earth,then use momentum conservation
It's not that simple. The speed of the exhaust in an inertial frame reduces as the rocket accelerates. You need to use (or to derive) the rocket equation Filip mentions.
 
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