Rollback Distance Calculation for a Car on a Slope

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A car traveling at 24.0 m/s on a 20.0-degree slope runs out of gas, prompting a calculation of how far it will coast uphill before rolling back down. The relevant equation is Vf^2 = Vi^2 - 2a(g*sin(20)(Xf-X0). There is uncertainty about the accuracy of the formula and the calculation of sin(20), which yields approximately 0.34. Participants express confusion regarding solving for Xf and the overall approach to the problem. Clarification on the formula and calculations is needed to determine the correct distance the car will coast.
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Homework Statement



A car traveling at 24.0m/s runs out of gas while traveling up a 20.0degree slope.
How far up the hill will it coast before starting to roll back down?

Homework Equations



Vf^2=Vi^2-2a(g*sin(20)(Xf-X0)

The Attempt at a Solution



I don't know if that is correct formula but I don't know how to solve for Xf
 
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Yes you may solve using this formula
 
when i enter in sin(20) my calculator is .34 is that on track? it doesn't seem right
 

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