Room in Spaceship: Apparent Paradox?

  • Thread starter Thread starter Superstring
  • Start date Start date
  • Tags Tags
    Paradox
Superstring
Messages
120
Reaction score
0
Imagine a room in a spaceship. At each end, a laser is set up that points toward the center. At the center of the room there is a double-sided light detector that is connected to a switch. When the switch is flipped, it completes a circuit which causes a light-bulb to turn on. If both laser beams hit the detector at the same time, the switch is flipped and the light turns on. If they hit at different times, the light remains off. The lasers are activated a remote control, also stationed at the center of the room.

From the reference frame of someone inside the ship, if they were to turn on the lasers then the beams would hit the detector at the same time and they would see the light turn on. However, if someone in a passing spaceship (passing in the same direction as the laser beams) were to watch this, they would see the beams hit the detector at different times and the light would not turn on.

So does the light turn on or not? Or both, somehow?
 
Physics news on Phys.org
Superstring said:
From the reference frame of someone inside the ship, if they were to turn on the lasers at the same time then the beams would hit the detector at the same time and they would see the light turn on.

I added the phrase in bold to clarify what I take you to mean here. The clarification is crucial, because it resolves the apparent paradox, like so:

Superstring said:
However, if someone in a passing spaceship (passing in the same direction as the laser beams) were to watch this, they would see the beams [STRIKE]hit the detector[/STRIKE] being turned on at different times [STRIKE]and the light would not turn on[/STRIKE] but still reaching the detector at the same time and they would also see the light turn on.

Again, I've added the corrections in bold and crossed out the parts that were incorrect i your statement of how things would look from the spaceship. So the light turns on regardess of who is doing the observing (as it should--actual physical experiments have to give the same results in all frames).
 
PeterDonis said:
I added the phrase in bold to clarify what I take you to mean here. The clarification is crucial, because it resolves the apparent paradox, like so:



Again, I've added the corrections in bold and crossed out the parts that were incorrect i your statement of how things would look from the spaceship. So the light turns on regardess of who is doing the observing (as it should--actual physical experiments have to give the same results in all frames).

Thank you. That cleared up my confusion.
 
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...
Abstract The gravitational-wave signal GW250114 was observed by the two LIGO detectors with a network matched-filter signal-to-noise ratio of 80. The signal was emitted by the coalescence of two black holes with near-equal masses ## m_1=33.6_{-0.8}^{+1.2} M_{⊙} ## and ## m_2=32.2_{-1. 3}^{+0.8} M_{⊙}##, and small spins ##\chi_{1,2}\leq 0.26 ## (90% credibility) and negligible eccentricity ##e⁢\leq 0.03.## Postmerger data excluding the peak region are consistent with the dominant quadrupolar...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
Back
Top