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rms of sine wave = peak * 1/SQRT(2)
how is this derived from the rms equation?
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how is this derived from the rms equation?
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OK thanks. One more question: how did you integrate the sine-squared?
No. That was the trivial part. The rest is hard.mathman said:sin^2 + cos^2 =1. The rest is trivial.
Integral of sin^2 = integral of cos^2, so each must be 1/2 of the integral of 1.how do u use sin^2 + cos^2 =1 to evaluate the integral of sin² mathman?
The root-mean-square of a sine wave is a measure of its average amplitude. It is calculated by taking the square root of the mean of the squared values of the wave's amplitude over a given period of time.
The RMS of a sine wave is important because it represents the effective or DC value of the wave. It is commonly used in electrical engineering and physics to calculate power consumption and to compare the amplitudes of different waves.
The peak amplitude of a sine wave is the maximum value it reaches in either the positive or negative direction. The peak-to-peak amplitude is the difference between the highest and lowest values of the wave. The RMS, on the other hand, takes into account the entire range of values and provides a more accurate representation of the wave's amplitude.
No, the RMS of a sine wave cannot be negative. Since the RMS is calculated by taking the square root of the mean of squared values, it will always result in a positive value.
The RMS of a sine wave is calculated by taking the square root of the mean of squared values of the wave's amplitude over a given time period. This can be represented by the formula RMS = √(1/T ∫(0 to T) x(t)^2 dt), where T is the period of the wave and x(t) is the amplitude at time t.