Root mean square velocity question

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Homework Help Overview

The discussion revolves around the relationship between root mean square (RMS) velocity and temperature in the context of gas laws, specifically at different temperatures (120 K and 480 K). Participants are exploring the relevant formulas and concepts related to this topic.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to identify the appropriate formula for calculating RMS velocity and its relation to temperature. Questions about how to proceed with the given formula and the relationship between pressure and temperature are raised.

Discussion Status

There is an ongoing exploration of how to connect the formula for RMS velocity with temperature using the ideal gas law. Some participants have provided guidance on expressing pressure in terms of temperature, while others are seeking clarification on the steps to take next.

Contextual Notes

Participants are working within the constraints of a homework help environment, emphasizing the need for individual effort and understanding rather than direct solutions.

Insiya
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If at 120 K the Vrms is v , then at 480 K it will be

a. 1
b. 2
c. 3
d. 4
Which formula is to be used here? Plz solve this.
 
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We don't solve anything here. We can help, but only if you show some effort.
 
Ok.. but I couldn't understand it.. The formula mentioned in my book is Vrms= radical 3P/density so...What to do next?
 
Are you saying there is no equation linking r. m. s. velocity and temperature that you know of?
 
No.. I am not saying this.. This formula also shows relation with temperature but how to continue..?
 
Perhaps you could express how pressure depends on temperature?
 
Pressure has direct relation with temperature
 
What is the equation?
 
PV=nRT
 
  • #10
Use this and the equation given for r. m. s. velocity to relate the latter with T.
 
  • #11
Any clue?
 
  • #12
The clue is in #10. The rest is just algebra.
 
  • #13
ok.. Thank U
 

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