Root test vs. ratio test question

cue928
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I am doing the following practice problem in prep for an exam:
sum from n=0 to infinity: (3^n)/(n+1)^n
The book says to use the ratio test on it, which I did, but would the root test also apply to this?
 
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The root test applies, and in fact is probably the simplest test to use in this case. What was your conclusion based on the ratio test?
 
cue928 said:
I am doing the following practice problem in prep for an exam:
sum from n=0 to infinity: (3^n)/(n+1)^n
The book says to use the ratio test on it, which I did, but would the root test also apply to this?


Well...

\sqrt[n]{\frac{3^n}{(n+1)^n}} =

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.
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I had initially changed it to be:
(3/(1+n))^n. Applying the nth square root, I got lim n approaches infinity 3/1+n = 0.
 
cue928 said:
I got lim n approaches infinity 3/1+n = 0.

Ok, so what's the conclusion?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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