Root3: Rewrite & Produce Non-trivial Equation + Show Irrationality

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The discussion revolves around rewriting the expression root(3) - 1 to derive a non-trivial equation for root(3). Participants suggest that root(3) can be expressed as x - 1 = 2/(x + 1), which is a non-trivial equation. They also explore the implications of expressing root(3) as a fraction m/n, leading to the equation m/n - 1 = 2/(m/n + 1). The conversation touches on whether this representation could lead to contradictions regarding the rationality of root(3). Overall, the goal is to demonstrate that root(3) is irrational through these mathematical manipulations.
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1)write root(3)-1 in another way,and use this to produce a non-trivial equation for root(3) in terms of itself

2)suppose m,n(m,n is natural numbers) are such that m/n=root(3),use (1) to write root(3)as another combination of m and n.
3)use (2) to show that root(3) in not rational.

Any hints appreciated..
 
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How about

\sqrt 3 - 1 = \frac {2}{1+\sqrt 3}?
 
Which, I think, would then give x- 1= \frac{2}{x+1} as a non-trivial equation for \sqrt{3}.

If \frac{m}{n}= \sqrt{3}, then \frac{m}{n}-1= \frac{2}{\frac{m}{n}+1}. Does that lead to anything?
 
Hmm. How do you define non-trivial?
 
thanx a lot!

thanks a lot to all you guys!
really appreciated..



HallsofIvy said:
Which, I think, would then give x- 1= \frac{2}{x+1} as a non-trivial equation for \sqrt{3}.

If \frac{m}{n}= \sqrt{3}, then \frac{m}{n}-1= \frac{2}{\frac{m}{n}+1}. Does that lead to anything?
 
I would consider anything other than x= \sqrt{3} to be "non-trivial"!
 
Another question

HallsofIvy said:
I would consider anything other than x= \sqrt{3} to be "non-trivial"!

root(3)=(m+3n)/(m+n), if m,n is allowed having the common factor,Does it lead to any contradiction?
 
i was wondering wut the answer would be for question 3) for general knowledge
 

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