Rotating parts of a motor have a moment of inertia

AI Thread Summary
The discussion revolves around calculating the common speed of rotation, change in angular momentum, change in angular kinetic energy, and the time required for a motor to regain optimum speed after connecting to a counter-rotating shaft. The moment of inertia of the motor is given as 15 kgm^2, with an optimum running speed of 1400 rev/min, while the shaft rotates at 600 rev/min. Participants are attempting to convert the speeds from rev/min to rad/s to apply the angular momentum equation. There is a noted uncertainty about the calculations and the necessity for showing work to verify the process. The conversation emphasizes the importance of clear calculations in solving the problem effectively.
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Homework Statement



The rotating parts of a motor have a moment of inertia of 15 kgm^2 and an optimum running speed of 1400 rev/min. When operating the motor is connected at optimum speed , by means of a clutch, to a shaft which has a counter rotation of 600 rev/min. The shaft has a mass of 80 kg and a solid diameter of 1200 mm.

i) Find the common speed of rotation of the two shafts, immediately after slippage has finished.
ii) Determine the change in angular momentum of the motor as the common speed is reached.
iii) Determine the change in angular kinetic energy of the motor as the common speed is reached.
iv) If the motor sends a torque of 220 Nm, find how long it will take for the system to regain optimum running speed for the motor.

Homework Equations



I1ω1=I2ω2?

The Attempt at a Solution



I have tried converting rev/min to rad/s and then trying to find out the common speed using angular momentum but don't know if is right?
 
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Well how are we supposed to know if you don't show your calculations?
 
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