Rotation of Axes: Point (x,y) to (X,Y)

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When the coordinate axes are rotated clockwise by an angle theta, the coordinates of the new point (X,Y) can be determined using trigonometric functions. A visual representation includes the original point (x,y) on the standard axes and the new axes positioned at angle theta. By drawing perpendiculars from the point to both the original and rotated axes, two right triangles are formed. The lengths of these perpendiculars can be expressed in terms of x, y, and theta, allowing for the calculation of y' as a function of these variables. This method effectively illustrates the transformation of coordinates due to axis rotation.
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Let a point be(x,y)

If the coordinate axes are shifted in clockwise direction by an angle theeta,what are the coordinate of the new point(X,Y).
 
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How about drawing a picture. Draw the x-axis horizontal, the y-axis vertical and mark the point (x,y). Now draw the x'-axis at angle \theta to the x-axis, y'-axis at angle \theta to the y-axis. Draw a perpendicular to the x-axis. Its length is y. Draw a perpendicular to the x'-axis. Its length is y'. You now have two right triangles and should be able to use trig functions to deternine y' as a function of x, y, and \theta.
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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