A friendly Brazilian has a mass of 150 kg. Being in Brazil, he rotates in a circle around the center of the earth once per day, The radius of this circle (which is essentially the radius of the Earth) is 6.40 x 10^6 m.
I have found that the normal force is 1.4649 x 10^3.
ac = v2/r , centripetal acceleration
v = (2[itex]\pi[/itex]r)/T , T is period of one revolution
The Attempt at a Solution
I only got to mg - Fn = mac
I know what the apparent weight is but I'm not sure about the normal force. If I can find this, then I can then find ac, v, and then T to find about the length of day.