Rotational kinetic energy of jupiter

AI Thread Summary
The discussion focuses on calculating the rotational kinetic energy of Jupiter, treating it as a uniform sphere with a rotational period of 9.81 hours. The user correctly identifies the necessary equations for angular velocity and moment of inertia, using Jupiter's mass of 1.898e27 kg and radius of 71,492,000 meters. However, they encounter an issue with obtaining the correct answer after substituting values into the rotational kinetic energy formula. The community suggests verifying unit consistency and arithmetic calculations to resolve the discrepancy. Accurate calculations are crucial for determining Jupiter's rotational kinetic energy.
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Homework Statement


What is the rotational kinetic energy of Jupiter? Assume Jupiter is a uniform sphere with a rotational period of 9.81 hr.


Homework Equations



I= 2mr^2/5
Krot= I*omega^2/2
omega= 2pi/T

The Attempt at a Solution


i found the omega using the equation above and the period given
Then i found the moment of inertia using the equation above as well. Took the mass as 1.898e27 kg. and the radius as 71492000 metres.

I substituted both of these into the equation of rotational kinetic energy and did not get the right answer. any help would be appreciated
 
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Sounds like you have the correct approach. Check your units and your arithmetic.
 
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