Rotational Motion of a pendulum

AI Thread Summary
The discussion focuses on calculating the rotational speed of a pendulum bob as it swings down, expressed in terms of mass, string length, angle, and gravity. The initial attempt at the solution involved the equation w = ((2ghl(cosθ - cosθi))^(1/2))/l, which was deemed incorrect due to the inclusion of height (h). Participants suggest simplifying the equation by ensuring proper notation, particularly using cos(θ) instead of cosθ. A hint from a software tool indicated that the correct answer should include the variable θ, which was missing in the initial response. The conversation emphasizes the importance of correct variable representation and simplification in achieving the right answer.
xxphysics
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Homework Statement


A pendulum is made of a bob dangling from a lightweight string of length ℓ. The bob is pulled sideways so that the string makes an angle θi with respect to the vertical, then released.

As it swings down, what is the rotational speed of the bob as a function of the changing angle θ? Use the notation l for the length of the string ℓ.
Express your answer in terms of the the variables m, l, θ, θi, and acceleration due to gravity g.

Homework Equations


h = l(cosθ - cosθi)
v=(2gh)^1/2
w = v/l

The Attempt at a Solution


I got w = ((2ghl(cosθ - cosθi))^(1/2))/l , but that was not correct. Are my equations wrong? Thanks
 
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xxphysics said:
I got w = ((2ghl(cosθ - cosθi))^(1/2))/l
How come there is still an h in there?
 
haruspex said:
How come there is still an h in there?
oh sorry ignore that. I entered it without it
 
xxphysics said:
oh sorry ignore that. I entered it without it
Then your answer looks ok to me. Do you know what the official answer is? Or do you enter it into a software package that simply says yes or no? If the second, maybe you need to simplify it a bit by cancellation, leaving l in the denominator only.
 
haruspex said:
Then your answer looks ok to me. Do you know what the official answer is? Or do you enter it into a software package that simply says yes or no? If the second, maybe you need to simplify it a bit by cancellation, leaving l in the denominator only.
I enter it on the computer. It gave me the hint "The correct answer involves the variable \texttip{\theta _}{theta_}, which was not part of your answer.", but I guess my computer isn't able to read that portion of the tip ? Not sure, but thank you
 
haruspex said:
Then your answer looks ok to me. Do you know what the official answer is? Or do you enter it into a software package that simply says yes or no? If the second, maybe you need to simplify it a bit by cancellation, leaving l in the denominator only.
How would you simplify it further since for the numerator the square root needs to be taken ?
 
xxphysics said:
I enter it on the computer. It gave me the hint "The correct answer involves the variable \texttip{\theta _}{theta_}, which was not part of your answer.", but I guess my computer isn't able to read that portion of the tip ? Not sure, but thank you
Sounds like it needs you to enter it as cos(θ) etc., not cosθ. Or maybe you did.
xxphysics said:
How would you simplify it further since for the numerator the square root needs to be taken ?
√x/x=1/√x
 

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