What is the Moment of Inertia for a Rod?

AI Thread Summary
The discussion revolves around calculating the moment of inertia (M.I.) for a rod system. Participants clarify the treatment of the farthest rod, suggesting it should be considered as a point mass at its center for accurate calculations. There is confusion regarding the total mass of the system and the radius of gyration, with one participant initially misreading the problem's requirements. The correct approach involves recognizing that the total mass is 3m, leading to a different calculation for the moment of inertia. Ultimately, the conversation emphasizes the importance of correctly interpreting the axis of rotation and the mass distribution in the system.
coldblood
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Hi friends,
Please help me in solving this problem, I'll appreciate the help.

The problem is as:

https://fbcdn-sphotos-g-a.akamaihd.net/hphotos-ak-ash3/q71/s720x720/1467427_1461727597387679_1141225220_n.jpg

Attempt -

https://fbcdn-sphotos-b-a.akamaihd.net/hphotos-ak-ash3/q71/s720x720/1472752_1461727710721001_1917071548_n.jpg

Thank you all in advance.
 
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You treated the rod furthest from the axis as a point mass at its centre.
Also, I think you have confused the mass per rod with the total mass.
 
haruspex said:
You treated the rod furthest from the axis as a point mass at its centre.
Also, I think you have confused the mass per rod with the total mass.

So what will with the farthest rod Should I take its moment of inertia as ml2/12(about center) + m(l√3/2)2

If I do so,

The total M.I. is found to be (3/2) ml2

Which gives radius of giration as l√(3/2)

But the answer is l/√2
 
coldblood said:
So what will with the farthest rod Should I take its moment of inertia as ml2/12(about center) + m(l√3/2)2
Yes.
If I do so,

The total M.I. is found to be (3/2) ml2

Which gives radius of giration as l√(3/2)

But the answer is l/√2
That's the other error I mentioned. If each rod has mass m then the entire structure has mass 3m. If its radius of gyration is k then its moment of inertia will be 3mk2.
 
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Well, I did a mistake in reading the question also. I thought that I have to calculate the moment of inertia of the system about the axis parallel to the plane of the structure.

If I have to find the M.I. of the system about an axis parallel, So what would the M.I of the farthest rod?
In that case should I treat it as a point mass situated at the center of the rod?
 
coldblood said:
Well, I did a mistake in reading the question also. I thought that I have to calculate the moment of inertia of the system about the axis parallel to the plane of the structure.

If I have to find the M.I. of the system about an axis parallel, So what would the M.I of the farthest rod?
In that case should I treat it as a point mass situated at the center of the rod?

Yes.
 
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