Rotational speed due to gravitational pull in earth's orbits

AI Thread Summary
In discussing the optimal orbit for achieving the highest rotational speed for a package, it is established that a lower orbit allows for greater speed due to proximity to Earth, as described by Kepler's third law. However, the significant atmospheric drag at low Earth orbit can hinder sustained orbital motion, leading to reentry rather than stable orbiting. The conversation emphasizes the need for mathematical relations that account for gravitational pull, distance, and atmospheric effects to accurately describe the scenario. Parameters such as altitude, velocity, and drag coefficients should be considered for a realistic model. Ultimately, while lower orbits provide speed advantages, they also introduce challenges that must be addressed.
y33t
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Hi All,

Assume we have a package that we want it in an orbit with highest possible speed. In which orbit (low,mid,high) the package will rotate faster ? Due to smaller distance, low Earth orbit should allow more speed but there is also more air friction there. What would be the mathematical relation to derive rotational speed dependent on other variables? What kind of parameters should be introduced for a more realistic description of the problem?

Thank you.
 
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This question does not belong in special and general relativity. Classical physics is more than capable of answering this question, which is where I have moved this thread.

The answer is simple: Lower. Kepler's third law.

What if the object gets so low that atmospheric drag becomes significant? Simple: The object is no longer orbiting. It's reentering the Earth's atmosphere.
 

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