Rough sketch of exponential graph without derivatives

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SUMMARY

The discussion focuses on sketching the function e^x + x - 2 to demonstrate that it has only one root. Participants suggest using graphical methods to visualize the intersection of the curve y = e^x + x and the line y = 2. By analyzing the behavior of the exponential function and linear components, it is established that the function intersects the line at a single point, confirming the existence of only one root. This approach emphasizes intuitive understanding over formal derivative techniques, which will be covered later in the course.

PREREQUISITES
  • Understanding of exponential functions, specifically e^x.
  • Basic knowledge of linear equations and graphing.
  • Familiarity with the concept of roots and intersections of graphs.
  • Experience with limits and asymptotes.
NEXT STEPS
  • Explore the properties of exponential functions, particularly e^x.
  • Learn about graphical methods for finding roots of equations.
  • Study curve sketching techniques in calculus.
  • Investigate the relationship between functions and their intersections.
USEFUL FOR

Students in introductory calculus courses, educators teaching graphing techniques, and anyone interested in understanding the behavior of exponential functions and their intersections with linear equations.

Batmaniac
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Homework Statement



Roughly sketch e^x + x - 2 to show that it has only one root. This is given before we learn derivatives and the curve sketching algorithm, but after we have gone through limits and asymptotes.


The Attempt at a Solution



Well, the graph of e^x - 2,is easy enough, a simple exponential graph shifted down by 2. But what does the +x do to the graph from there? I've no idea. I could sketch it using the curve sketching algorithm we learned in high school calculus, but we don't cover that for another month or so in this course so I know it's expected to be done by other methods (mostly intuition!), especially since it's just a really rough sketch they want.

- thanks
 
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Let [tex]y=x^2-3x+2[/tex] to find how many roots this eq'n has you would equate y to zero and solve right?
but what in fact you are really doing graphically is drawing the graph of the left side and the graph of the right side and finding where they intersect.

so for your situation
let [tex]y=e^x + x - 2=o[/tex] now there are many graphs you can draw to show that there is only one root.

you could put [itex]e^x + x=2[/itex] and draw the curve [itex]y=e^x + x[/itex] and the line [itex]y=2[/itex] and show that they intersect one point. Or you could draw [itex]y=e^x[/itex] and the line [itex]y=2-x[/itex] and so forth...So pick which ever combination you find easiest or most useful to draw
 
That's an awesome method for finding roots of complex functions. I never knew you could break them up like that.

Thanks a lot!
 

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