dog6880 said:
Ok tell me if i understand this correctly:
Object A is emitting light
Object B is moving away from it at half the speed of light (constant speed)
Object C is stationary
Object B and C are 5 light years away from Object A (B just passes C as the light is initially emitted)
the light will reach both Object B and C at the same time even though 5 years later when it does arrive at object B object C is 2.5 light years away from Object B. (i assume this is only from the perspective of Object B cause the light is not really there yet)
I hope i got it wrong cause that's crazy. Why did i pick up this damn book?
"Stationary" doesn't have any absolute meaning in relativity, every object is stationary in its own rest frame. But perhaps you just meant that object C is stationary with respect to object A. In this case you have to consider the issue of
length contraction, which says that if the distance between A and C is 5 light years in their own rest frame, in the rest frame of object B the distance between A and C is shorter by a factor of \sqrt{1 - v^2/c^2}, in this case 0.866, so the distance from A to C in B's frame is only 5*0.866 = 4.33 light years. You also have to consider the issue of the
relativity of simultaneity, which says that if the event of B and C being next to each other is simultaneous with the event of A emitting the light according to the B/C rest frame, then these two events are
not simultaneous in B's frame, instead the event of A emitting the light doesn't happen until 2.887 years have passed since B passed C according to this frame (I calculated this using the
Lorentz transformation, which I can explain if you want), so B is now at a distance of 4.33 + 0.5*2.887 = 5.77 light years from A. So the light will take 5.77 more years to reach B in this frame, meaning it reaches B at a total of 2.887 + 5.77 = 8.66 years after B passed C, in B's frame.
Meanwhile, back in the rest frame of A and C, we calculate that 10 years after B passed C, B is now 10 light years away from A and the light is also 10 light years away from A, so that's how long it takes the light to reach B in this frame. But to predict what B's clock reads when the light catches up with it according to the A/C rest frame, we have to take into account the issue of
time dilation, which says that B's clock is running slow by a factor of 0.866 in this frame. So, 10 years after B passed C in this frame, B's clock will only show 8.66 years having passed since B passed C, which agrees with what we found above in B's rest frame.