I'm reading Landau and Lifgarbagez's Mechanics book and am having a hard time proving the following: On page 53, they present theta_0 = arccos( ... ). As described on page 48 eqn 18.2 the integral should produce this theta_0. However, I am not quite sure what r_min is? On page 48, they say 'It should be recalled that r_min is a zero of the radicand. I *think* that means rmin is a turning point, yes? On page 36, they integrate eqn 18.2 (I assume with the same limits: rmin to inf), however notice there is an extra term. (Also they integrated it for U(r) = - alpha/r, but that is just a sign change). Furthermore, eqn 15.14 on page 38 (evaluated for a repulsive potential U = +a/r) shows: p/r = -1 + e cos(phi). However, if I am not mistaken, for Rutherford's problem, cos(phi) = -1/e, where does the p/r term go? Here's a summary of what I am asking if it didn't make sense: 1) I am trying to find phi_0 for a repulsive potential U(r) = a/r 2) Using Kepler's problem with the signs changed, phi_0 on page 53 and phi on the top of page 36 don't seem to match (different limits of integration?) I did of course convert to E = 1/2 m vinf^2 and M = mv_inf p, but that still doesn't appear to yield the same result.