S.H.M Homework - Why Consider One Mass Only?

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The discussion focuses on the dynamics of a system with two masses connected by a spring, questioning why only one mass is considered in the analysis. Participants clarify that while both masses stretch the spring simultaneously, the motion of each mass can be analyzed separately. The key point is that the spring's total stretch is 2x, leading to a force of -2kx acting on each mass. The confusion arises regarding the use of 'ma' instead of '2ma' in the equations, with the explanation emphasizing the separate analysis of each mass. Ultimately, the analysis simplifies to understanding the forces and motion of each mass in relation to the spring's stretch.
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Homework Statement



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Homework Equations


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The Attempt at a Solution


I know how to show ,but I don't understand why we consider one mass only

[PLAIN][PLAIN]http://b.imagehost.org/0195/questionb.jpg
 
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That looks like two masses connected by a spring. You describe the motion of each mass (with respect to the center) separately, but they are definitely connected.
 
Doc Al said:
That looks like two masses connected by a spring. You describe the motion of each mass (with respect to the center) separately, but they are definitely connected.

they strecthed at the same time.
so

ma =-kx
a=-(k/m) x
ma=-kx
a= -(k/m)x

but I don't know how to combine as

a=-(2k/m)x

I think it should be a=-(2k/2m)x = -(k/m)x
 
I believe that instead of stretching both, you could hold one down and stretch the other twice as far.
 
Feldoh said:
I believe that instead of stretching both, you could hold one down and stretch the other twice as far.

That means

ma = -k(2x)?
a=(-2k/m)x ?

I am doubt why ma is used instead of 2ma ?
the whole mass of system is 2m ?
 
mysqlpress said:
they strecthed at the same time.
so

ma =-kx
a=-(k/m) x
ma=-kx
a= -(k/m)x
If x is the displacement of each mass, the amount of stretch in the spring is 2x.
 
Doc Al said:
If x is the displacement of each mass, the amount of stretch in the spring is 2x.
but why should we use

ma=-2kx
but not
2ma=-2kx ?
since there are two bob with mass m..
 
mysqlpress said:
but why should we use

ma=-2kx
but not
2ma=-2kx ?
since there are two bob with mass m..
Because we are analyzing the motion of each mass separately:

What's the mass? m
What's the stretch of the spring? 2x
What's the force on each mass? -2kx
 
Doc Al said:
Because we are analyzing the motion of each mass separately:

What's the mass? m
What's the stretch of the spring? 2x
What's the force on each mass? -2kx

Thanks Doc Al.
you do help me a lot :devil:
 
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