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karush

Gold Member

MHB

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3.7.4. The sum of two positive numbers is 16.

What is the smallest possible value of the sum of their squares?

$x+y=16\implies y=16-x$

Then

$x^2+(16-x)^2=2 x^2 - 32x + 256$

So far

... Hopefully

What is the smallest possible value of the sum of their squares?

$x+y=16\implies y=16-x$

Then

$x^2+(16-x)^2=2 x^2 - 32x + 256$

So far

... Hopefully

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