Satellite Link Design: Find Tx for Satellite & Ground Sides

AI Thread Summary
The discussion focuses on calculating the transmission power (Tx) for both satellite and ground sides using Shannon's equation, given a bit rate of 9600 bits/second and a channel bandwidth of 10 MHz. The initial attempt at solving the problem led to an incorrect signal-to-noise ratio (S/N) calculation of -31.77 dB. Concerns were raised about the validity of the given bit rate, as 9.6 kbps seems incompatible with a 10 MHz bandwidth. Participants are seeking clarification on potential mistakes in computation, interpretation of Shannon's equation, or the overall approach to the problem. The conversation highlights the importance of ensuring that parameters align correctly for accurate satellite link design.
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Homework Statement



Given:
Bit rate = C = 9600 bits/second
Channel Bandwidth = B = 10 MHz
Find Tx for satellite side and ground side

Homework Equations



Shannon's equation: C = B*log {1+(S/N)} (log is to the base 2)

The Attempt at a Solution



Well this is how I decided to approach the problem
Use Shannon's equation> calculate (S/N)> account for all the losses> calculate EIRP> calculate Tx
But I seem to be going wrong in the beginning itself
After computation, I calculated (S/N) to be -31.77 dB or -1.77 dBm (which is definitely wrong!)

Could you please point out the mistake? Is it in my computation or my interpretation of the Shannon's equation? Or is my entire approach gravely wrong?
 
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Bit rate = C = 9600 bits/second
Channel Bandwidth = B = 10 MHz

IMHO the given bitrate is not correct. 9,6 kbps carrier can't take 10Mhz of bandwidth.
 
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