Satellite X and Y Orbital Period - Answer B: 1.4x10^6s

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AI Thread Summary
Two satellites, X and Y, orbit a planet, with satellite X having a period of 3.6x10^5 seconds and an orbital radius of 7.5x10^8 meters. To find the orbital period of satellite Y, which has an orbital radius of 3.0x10^9 meters, Kepler's third law is applied. The correct calculation leads to an answer of 1.4x10^6 seconds for satellite Y's orbital period. There is clarification that the "period of revolution" for satellite X is indeed the same as its "orbital period." The discussion emphasizes the importance of correctly applying Kepler's third law in solving such problems.
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Homework Statement


Two satellites, X and Y, are placed in orbit around a planet. Satellite X has period of revolution of 3.6x10^5s and an orbital radius of 7.5x10^8m. If the orbital radius of satellite Y is 3.0x10^9m, what is the orbital period?

A) 9.1x10^5s
B) 1.4x10^6s
C) 2.9x10^6s
D) 5.2x10^7s

Homework Equations


Kepler's third law equation:
(T1/T2)^2 = (R1/R2)^2


The Attempt at a Solution


For this question what I did was use Kepler's third law and the answer I got was "B". But I was wondering is this correct because satellite X it says it has a "period of revolution of 3.6x10^5s", is this the same as "orbital period"?
 
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Inertialforce said:
For this question what I did was use Kepler's third law and the answer I got was "B". But I was wondering is this correct because satellite X it says it has a "period of revolution of 3.6x10^5s", is this the same as "orbital period"?

they are one and the same.
 
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