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DennisN
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DrClaude said:I'm not sure I believe in ##\pi##. The arguments I've seen for it were pretty much circular.
Please note that the use of [itex]\pi , \sqrt{2}[/itex] or [itex]e[/itex] in any argument automatically makes it irrational.
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For any real time process, ##it## is complex.DennisN said:Please note that the use of [itex]\pi , \sqrt{2}[/itex] or [itex]e[/itex] in any argument automatically makes it irrational.
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Acceptable. Every transcendent argument is irrational.DennisN said:Please note that the use of [itex]\pi , \sqrt{2}[/itex] or [itex]e[/itex] in any argument automatically makes it irrational.
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If you have a problem, you need ##\pi##!DrClaude said:I'm not sure I believe in ##\pi##. The arguments I've seen for it were pretty much circular.
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How many reals could Cantor count if Cantor could count reals?DrGreg said:I can't count the number of irrational arguments out there.
Not great, but "countables" doesn't scan...
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I thought I saw stars in the picture, but my screen was dusty :(fresh_42 said:
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jbriggs444 said:For any real time process, it is complex.
For a while, dialing an unassigned MIT phone number produced the message "I'm sorry, the number you have dialed is imaginary. Please multiply by i and dial again."
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I is on the 4 key on a phone keypad. So dial *4 after or 4* before?Vanadium 50 said:For a while, dialing an unassigned MIT phone number produced the message "I'm sorry, the number you have dialed is imaginary. Please multiply by i and dial again."
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If the original number is imaginary with a positive imaginary component then taking the complex conjugation and multiplying by i will make it real and positive, but multiplying it with the complex conjugate of i will work as well.
i*##\cdot##[number] and [number]*##\cdot##i are both fine.
i*##\cdot##[number] and [number]*##\cdot##i are both fine.
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iQ
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Since the Q in IQ stands for quotient, I think all IQs are rational by definition. But he could be completely imaginary.BillTre said:Does that mean your irrational?
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I am real. You said you weren't.Drakkith said:IQ = Imaginary Quotient? Psh! Get real!
(Now we have an argument. Can anyone think how to get a modulus into this?)
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All wrong. It is an element of a ##Q-##algebra. It is generated by
$$
\{\,IQ , ABQ,BBQ,Q\#,Q1,Q2,Q3,Q4,QB,QED,QLD,QM,QFT,QSO,QPR\,\}
$$
$$
\{\,IQ , ABQ,BBQ,Q\#,Q1,Q2,Q3,Q4,QB,QED,QLD,QM,QFT,QSO,QPR\,\}
$$
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It's what you wait in when your Lasik doctor has three patients ahead of you.fresh_42 said:All wrong. It is an element of a ##Q-##algebra. It is generated by
$$
\{\,IQ , ABQ,BBQ,Q\#,Q1,Q2,Q3,Q4,QB,QED,QLD,QM,QFT,QSO,QPR\,\}
$$
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Not for a mathematician.DrClaude said:Isn't * complex conjugation?
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Experimental physicist: I understand ##x\gg 1##, but what does ##x\rightarrow\infty## mean?
Mathematical physicist: I understand ##x\rightarrow\infty##, but what does ##x\gg 1## mean?
Practical theoretical physicist: I understand both, but what's the difference?
Mathematical physicist: I understand ##x\rightarrow\infty##, but what does ##x\gg 1## mean?
Practical theoretical physicist: I understand both, but what's the difference?
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I knew I'd actually done this joke before: it's just in a slightly different context.Ibix said:
DennisN
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I don't know about @Drakkith , but my number of friends [itex]f[/itex] can be written as [itex]f = a + bi[/itex], where [itex]a[/itex] is my number of real friends and [itex]b[/itex] my number of imaginary friends. As long as [itex]a > b[/itex], I consider the situation acceptable. I sometimes get into an argument with my friends. It's usually resolved as [itex]arctan (b/a)[/itex].BillTre said:Does that mean your irrational?
or imaginary?
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Your arguments are so limited.a>b
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DennisN
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As long as the nose is pointing down they are not going to space today attack anyone.
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