Second highest frequency in a sound pipe

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Homework Help Overview

The discussion revolves around determining the second highest frequency in a sound pipe, with participants exploring the implications of the problem statement and the relevant equations related to sound frequency and wavelength.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the calculations related to frequency, questioning the interpretation of the problem statement regarding "second highest" versus "second lowest" frequency. There are attempts to clarify the values used for the speed of sound and the length of the pipe.

Discussion Status

The discussion is active, with participants providing feedback on each other's reasoning and calculations. Some guidance has been offered regarding the interpretation of the frequency terms, and there is acknowledgment of potential confusion in the wording of the problem.

Contextual Notes

Participants note the importance of using correct units and the potential for misinterpretation in the problem's phrasing. There is a recognition of the common vernacular that may lead to confusion in a physics context.

Bolter
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Homework Statement
See below
Relevant Equations
Speed = frequency x wavelength
So here is my question

Screenshot 2020-03-13 at 16.57.48.png

Screenshot 2020-03-13 at 16.57.52.png

Have tried it and got these as my answers

IMG_4089.JPG


Have I done part b) correctly over here to find the 2nd highest frequency?

Any help would be much appreciated! Thanks
 
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Bolter said:
Homework Statement:: See below
Relevant Equations:: Speed = frequency x wavelength

So here is my question

View attachment 258637
View attachment 258638
Have tried it and got these as my answers

View attachment 258639

Have I done part b) correctly over here to find the 2nd highest frequency?

Any help would be much appreciated! Thanks
You were doing fine as far as 3c/(4L), but I don't understand the numbers you plugged in for c and L.

By the way, what you have (almost) calculated is the second lowest frequency, which is what the question should have asked for. There is no highest frequency.
 
haruspex said:
You were doing fine as far as 3c/(4L), but I don't understand the numbers you plugged in for c and L.

By the way, what you have (almost) calculated is the second lowest frequency, which is what the question should have asked for. There is no highest frequency.

Ah yes I see why the question should’ve meant second lowest frequency and not second highest

For the c and L values I have plugged in, these are just the speed of sound (which is 340 m/s) and length of the sound sound pipe in mm (I converted them back into meters to keep in SI units)
 
Bolter said:
For the c and L values I have plugged in, these are just the speed of sound (which is 340 m/s) and length of the sound sound pipe in mm (I converted them back into meters to keep in SI units)
Ah, sorry, I misread the question. I was looking at data in the first part.
Your answers are fine.
 
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Bolter said:
Ah yes I see why the question should’ve meant second lowest frequency and not second highest

I completely agree what second highest should mean, but I can’t help point out the screwy confusions of how people actually use language. In the common vernacular people will sometimes say “second highest” when they mean “second in height”, so the “third highest rung on the ladder” is understood to be counted from the bottom. Very poor choice for a physics problem, but not unusual for English.
 
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Cutter Ketch said:
“second highest” when they mean “second in height”
Hmm... I would use those interchangeably, both meaning second from the top.
 

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