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## Homework Statement

Find the general solution for the following differential equation:

y'' + x(y')^2 = 0.

## Homework Equations

Integration, differentiation...

## The Attempt at a Solution

Usually for these sort of DE you could use the substitution v(x) = y'(x) and this would simplify such an equation to a first order DE. The (y')^2 part is throwing me off as this would give the equation:

v(x)' + x(v(x))^2 = 0.

This would be grand if it weren't for the v(x)^2 term. Any ideas on how to get around this? Thanks.