1. The problem statement, all variables and given/known data Find the general solution for the following differential equation: y'' + x(y')^2 = 0. 2. Relevant equations Integration, differentiation... 3. The attempt at a solution Usually for these sort of DE you could use the substitution v(x) = y'(x) and this would simplify such an equation to a first order DE. The (y')^2 part is throwing me off as this would give the equation: v(x)' + x(v(x))^2 = 0. This would be grand if it weren't for the v(x)^2 term. Any ideas on how to get around this? Thanks.