Jun 27, 2006 #1 boarie Messages 7 Reaction score 0 Dear all I'm a newbie here...having some prob and hope to have your expert advice on how to solve the equation attached. Thx in advance! Attachments equ6-27-2006-3.47.09 PM.jpg 4.9 KB · Views: 507
Dear all I'm a newbie here...having some prob and hope to have your expert advice on how to solve the equation attached. Thx in advance!
Jun 27, 2006 #2 J77 Messages 1,091 Reaction score 1 Do you want a general solution, or have you been given, eg., m=(m1,m2,m3), r=(r1,r2,r3), or have you specific values for the vectors m and r? Either way, do the cross product first, then divide by the scalar magnitude, then apply the curl function.
Do you want a general solution, or have you been given, eg., m=(m1,m2,m3), r=(r1,r2,r3), or have you specific values for the vectors m and r? Either way, do the cross product first, then divide by the scalar magnitude, then apply the curl function.
Jun 27, 2006 #3 boarie Messages 7 Reaction score 0 hi J77 Thx for your reponse.. appreciate your advice... In fact, the solution to the above is given as attached... I can't seem to derive to the stated form... Would really appreciate if any guru can shed some light... Attachments equation6-27-2006-10.16.32 PM.jpg 6.4 KB · Views: 489
hi J77 Thx for your reponse.. appreciate your advice... In fact, the solution to the above is given as attached... I can't seem to derive to the stated form... Would really appreciate if any guru can shed some light...
Jun 28, 2006 #4 J77 Messages 1,091 Reaction score 1 Quick reply, but to me the transformation seems to lie in using Lagrange's formula: a\times(b\times c)=b(a\cdot c)-c(a\cdot b) ie. "BAC minus CAB"
Quick reply, but to me the transformation seems to lie in using Lagrange's formula: a\times(b\times c)=b(a\cdot c)-c(a\cdot b) ie. "BAC minus CAB"