Seemingly simple kinematics exercise

AI Thread Summary
The discussion revolves around a kinematics problem involving a rigid body sliding along orthogonal runners. The main challenge is determining the velocities of points A and C, the position of the instantaneous rotation center, and the conditions for point D's horizontal velocity to be zero. Initially, confusion arises regarding the instructor's solution, particularly the assumption about the center of rotation at point B. However, it is clarified that in rigid body dynamics, angular velocity is independent of the reference point, resolving the misunderstanding. The participant ultimately gains clarity on the problem's geometric relationships and the application of angular velocity.
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Homework Statement


Rigid body
The plane rigid body ABCD shown in the figure has rectangular shape and
slides along the orthogonal runners X, Y. The points A and B are always in
contact with the ranners.
Data: ω=3 rad/s (angular velocity counterclockwise); \Theta=30°; AB=CD=1m;
AD=CB=0.5m.
Determine:
The A and C velocities;
The position of instantaneous rotation center;
The value of \Theta for which the horizontal velocity component of D is null.

30vke4h.jpg


Homework Equations



Fundamental geometric identities

The Attempt at a Solution



Without knowing the center of rotation or the relevant velocities a priori I don't know how one can be solved for the other. So really, I can't make it past the first step.

The instructor gave us this solution which to me makes no sense.

2n86kox.jpg


He claims that Va = Va/b + Vb

and that Va/b = ω*AB

But this makes no sense since it assumes the center of rotation is at point B, or else Va/b wouldn't be given as the product of ω times the length of segment AB.

Am I missing something or did the instructor forget to inform us that ω refers to point B?
 
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I may not get chance to come back to this for a few days and I'm not even 100% sure but...

Lets call the instantaneous center of rotation point O. I believe the walls must be tangential/right angles to OB and OA.
 
Here's the (sloppy) solution as given to us. Does this make any sense?
 

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Hrm, I was completely overlooking the fact that in rigid bodies and angular velocity and angular acceleration are independent of the reference point of the body.

It makes sense now.
 
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