Separately excited shunt generator

AI Thread Summary
A separately excited shunt generator with a nameplate data of 50kW, 125V, armature resistance of 0.01 ohms, and field resistance of 16 ohms is being analyzed. The discussion focuses on calculating the full load armature current, the electromotive force (EMF) generated at full load, and the power dissipated in both the shunt field and the armature. The initial step involves sketching the equivalent circuit to demonstrate understanding of the DC shunt generator. The participant found that after redrawing the circuit, the calculations became straightforward. Understanding the circuit is crucial for accurate calculations in electrical engineering.
andrew7447
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I have a question that iv been stuck on for wile. I am in year 2, electronic engineering and I am having a little trouble with this.

A separately excited shunt generator has the following nameplate data, 50kW, V(FL) = 125, R(A) = .01 ohms, R(F) = 16 ohms and an excitation voltage of 125 VDC.

Calculate the full load armature current
The amount of EMT generated at full load
Power dissipated in the shunt field
Power dissipated in the armature
 
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Step 1 is to sketch the equivalent circuit and mark on it the data you are given. This shows that you at least understand what a DC shunt generator is.
 
thanks, i looked at it for a bit and redrew it, then realized how easy it actually was.
 

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