- #1
physicsgal
- 164
- 0
n = number of items
pay scale #1
tn = n$0.65
so if n = 10, tn = $6.50
pay scale #2
$0.10 for each item, plus 0.05 for each additional item. so for the 2nd sale she'd make 0.15, third she'd make 0.20, etc.
if tn = 1. then it = 0.10
so 2 = 0.15 + 10 = 0.25
3 = 0.20 + 0.25 = 0.40
4 = 0.30 + 0.40 = 0.70
and so on..
so what's the formula for pay scale #2?
for the first part of the formula i have:
tn = 0.10 + 0.05n-1 and then to that i have to add the previous number (n-1)?
and at what point is pay scale #2 better than pay scale #1 (i got after 23 using the amy-method)
any help is appreciated!
~Amy
pay scale #1
tn = n$0.65
so if n = 10, tn = $6.50
pay scale #2
$0.10 for each item, plus 0.05 for each additional item. so for the 2nd sale she'd make 0.15, third she'd make 0.20, etc.
if tn = 1. then it = 0.10
so 2 = 0.15 + 10 = 0.25
3 = 0.20 + 0.25 = 0.40
4 = 0.30 + 0.40 = 0.70
and so on..
so what's the formula for pay scale #2?
for the first part of the formula i have:
tn = 0.10 + 0.05n-1 and then to that i have to add the previous number (n-1)?
and at what point is pay scale #2 better than pay scale #1 (i got after 23 using the amy-method)
any help is appreciated!
~Amy