- #1

tony873004

Science Advisor

Gold Member

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First I computed the combined resistance of the parallel resistors and got 4.54 kOhms. Then I added this to 10.5 to get 15.04 kOhms total resistance.

So from Ohm's law, the total current is I=V/R = 16.5 / 15040 = 1.0971 x 10

^{-3}A.

I get potentials at A, B, and C of 16.5, 11.5, and 0 volts.

I think this is correct so far.

To find the current through each resistor:

For the 10.5 kOhm resistor, since it is in series, it makes sense to me that the current through this resistor must be equal to the total current: 1.0971 x 10

^{-3}A. And that the current running through the parallel pair must also be 1.0971 x 10

^{-3}A. But the voltage across this resistor is 16.5-11.5, or 5v. Using Ohm's law, I=V/R, I get 5/10500 = 0.000476 A

Which way is correct???

Thanks