Series expansion for 2D dipole displaced from the origin

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 2K views
dilloncyh
Messages
39
Reaction score
0
I learn that we can expand the electric potential in an infinite series of rho and cos(n*phi) when solving the Laplace equation in polar coordinates. The problem I want to consider is the expansion for the potential due to a 2D line dipole (two infinitely-long line charge separated by a small distance). In the attached image, I have written down the potential due to a line dipole (I'm pretty sure it's correct, at least the dot product and the dependence on D and r). Now I place the perfect line dipole at a position (-x0,0), and I want to calculate the potential in terms of the infinite series. The problem is that the coefficient An is different depending on whether rho is bigger than or smaller than x0 when I solve the integral using contour integral (again, pretty sure the definite integral is done correctly). At the 'imaginary' boundary of rho=x0, the potential calculated using the two different An should give the same results, but now they differ by a sign. Why is that? What have I done wrong?
 

Attachments

  • dipole_problem.jpg
    dipole_problem.jpg
    31.5 KB · Views: 568
Physics news on Phys.org
It's not the same A_n for each case. The expansion has one set of coefficients for r^n and a second set, B_n, for 1/r^n.