Set Containing Itself: X and {X}

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A set is not allowed to has itself as a member: X \notin X. But I wonder if this is allowed: \{X\} \in X.
 
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Outlined said:
A set is not allowed to has itself as a member: X \notin X. But I wonder if this is allowed: \{X\} \in X.

Neither are allowed in ZF. But there are theories in which both are allowed -- for example, ZF without the Axiom of Foundation.
 
It's not allowed since the set {{X},X} have no disjoint element of itself.
 
CRGreathouse said:
Neither are allowed in ZF. But there are theories in which both are allowed -- for example, ZF without the Axiom of Foundation.

Is it possible to construct such a set in ZF without Axiom of Foundation?
 
No -- such a construction would amount to a theorem of anti-foundation.

Specific axioms of anti-foundation may provide constructions, however.
 
The confusion here, I think, is in the designator "X", where this letters is trying to stand for both an element as well as a set. {X} in X means the element X as a set is found within the set, which violates the axiom of regularity, otherwise called "axiom of foundation", designed to prevent such expressions.
 
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