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I2 (s) + 2e- = 2I- (aq) reduction potential is +0.53

Zn2+ (aq) + 2e- = Zn (s) reduction potential is -0.76

using nerntz I get

E = 1.29 - (0.0257/2)(ln (2.24/0.1)

E= 1.2500

What would could I use to get the I and Zn ions??? Also, would the Zn be the solution that should be 2.24 molar or the I???

Would KCl be a good salt bridge?

Thanks

Nautica

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# Setting up a galvanic cell (1.25V)

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