Shell model determining spin and parity

Confundo
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shell model determining spin and parity - urgent

Homework Statement



Find the spin and parity of _{20}^{41}Ca and _{20}^{40}Ca

Homework Equations



http://hyperphysics.phy-astr.gsu.edu/hbase/Nuclear/shell.html


The Attempt at a Solution



For _{20}^{41}Cawe've an odd number of neutrons which will lie in 1f(7/2) level
so we have spin 7/2 and parity -

For _{20}^{40}Ca both the unpaired neutron and proon will be in the 1d(3/2) level which has parity +, do I need to add together the two spins in this level. So I'd get spin 3 with parity +.
 
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Thinking about it since the shell is full it can't contribute to spin.
 
Ca-40 has two closed shells, and since then it should have 0+ according to the shell model, right?
 
Confundo said:
Thinking about it since the shell is full it can't contribute to spin.

Yes, I think.

If we had something like _{21}^{42}X. Then we'd have an odd neutron and odd proton in the 1f_{7/2}, the spins would add and we'd have spin 7 and parity -1?
 
why negative parity?
 
Oh yeah. Should multiply the parities and thus get positive parity right? Basically the angular momentums are "parallel".
 
You can also have J_tot = 6,5,4,3,2,1,0.

Remember how to add two angular momenta.
 
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