Why Can't SHM Explain a Ball Falling Through Earth's Radius?

AI Thread Summary
The discussion centers on the limitations of simple harmonic motion (SHM) in explaining the behavior of a ball falling through a hole in the Earth. It highlights that SHM is typically applicable for small displacements, where force is linearly proportional to displacement. However, in this scenario, the displacement is significant, potentially comparable to the Earth's radius, raising questions about the validity of the linear approximation. Participants emphasize that the standard model assumes uniform density and a small hole, which may not hold true for larger displacements. The conversation ultimately seeks to clarify the role of higher-order terms in the force equation when considering larger displacements.
Kolahal Bhattacharya
Messages
133
Reaction score
1
We all know that a ball when dropped into a straight hole through the earth, it begins shm.The question I want to raise here is we know that SHM happens when displacement is very small so that F(x) depends only on the linear term kx and not on the higher order terms:x62, x63 etc.Here the displacement is very big, may well be compared to The Earth's radius.where I am going wrong?
 
Physics news on Phys.org
What higher order terms are you talking about? In the usual "ball dropped through a hole through the Earth" problem, we assume a uniform density and small hole, so that F(x) = kx throughout the motion.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top