Shockwave Question: Solving Mach 3 Plane 20Km Above Person

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To solve the problem of a Mach 3 jet at 20,000 meters, the time for the shock wave to reach the person is calculated using the speed of sound in air, which is 335 m/s. The initial calculation of 59.7 seconds is incorrect due to an error in the speed of sound used. The correct time to encounter the shock wave is approximately 56.3 seconds. Additionally, the position of the plane when the shock wave is heard needs to be determined based on its speed and travel time. Accurate calculations are essential for resolving discrepancies in the answers.
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Homework Statement


A supersonic jet traveling at Mach 3.00 at an altitude of
20 000 m is directly over a person at time t ϭ 0, as in
Figure P17.43. (a) How long will it be before the person
encounters the shock wave? (b) Where will the plane be
when it is finally heard? (Assume that the speed of
sound in air is 335 m/s.)



Homework Equations





The Attempt at a Solution


So I figured it would just be the time for sound to travel from the plane to the ground, or t = d/v = 20 000m/355m/s, but that gives me 59.7s, and the answer book says 56.3s. What am I doing wrong?
 
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