Shooting an arrow in the direction of the gradien

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If you are given a point (1,2,9), and a gradient <2,1,2>. How can you tell that if you show an arrow, it would hit the point (5,4,13). The arrow is being shot in the direction of the gradient.

where f(x,y,z)= x^2+y^2/4+z^2/9
 
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chaotixmonjuish said:
If you are given a point (1,2,9), and a gradient <2,1,2>. How can you tell that if you show an arrow, it would hit the point (5,4,13). The arrow is being shot in the direction of the gradient.

where f(x,y,z)= x^2+y^2/4+z^2/9
What does f have to do with the motion of the arrow?
 
I just included that to show how I calculated the gradient.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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