Short Answer SHM of diatomic molecule

AI Thread Summary
In the discussion about the short answer problem on the simple harmonic motion (SHM) of a diatomic molecule, key points include the requirement to demonstrate that the momenta of two identical atoms relative to their center of mass are equal and opposite, resulting in p and -p. The total kinetic energy of the two atoms must be shown to equate to that of a single object with half the mass and the same momentum. Additionally, when the atoms have different masses, the concept of reduced mass is introduced, defined as (m_1)(m_2)/(m_1+m_2). The participant expresses uncertainty about how to approach these problems, particularly in applying the relevant equations and concepts. Overall, the discussion highlights the challenges faced in understanding SHM in diatomic molecules.
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Homework Statement



Two identical atoms in a diatomic molecule vibrate as harmonic oscillators. However, their center of mass, midway between them, remains at rest.

1)Show that at any instant, the momenta of the atoms relative to the center of mass are p and -p

2)Show that the total kinetic energy K of the two atoms at any instant is the same as that of a single object with mass m/2 with a momentum of magnitude p .

3)If the atoms are not identical but have masses m_1 and m_2, show that the result of part (a) still holds and the single object's mass in part (b) is (m_1)(m_2)/(m_1+m_2). The quantity (m_1)(m_2)/(m_1+m_2) is called the reduced mass of the system.

Homework Equations



Energy= 1/2mv^2 + 1/2kx^2 = 1/2kA^2
Momentum= p= mv
Period= T = 2pi (m/k)^(1/2)

The Attempt at a Solution



This is a short answer problem and I really don't know how to go about this for sure. I think that you can assume that it is working like a spring.

1) I don't know how to show any work for number one, but would it be p= -p because there are no external forces acting? They are the same atoms, so they have to have the same mass and velocity and p=mv.

2)For this all I think is that the KE of the single object would be:
1/2(m/2)v^2= 1/2kA^2. This is for the case when x=0, so there is no potential energy from the spring.

3)This I have no idea.

We really haven't been over anything like this in class, so I am not sure what to do. Thanks for any help.
 
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