Short Grade 12 Gravitational Problem

AI Thread Summary
Planet V has a year lasting 360 days, while Planet X has half the mass and triple the radius. The derived formula for orbital period incorporates gravitational constants and radius, leading to the equation Tx = sqrt((2)(3)^3(360)^2) for Planet X's year. There is some confusion regarding whether the mass of the planet affects the calculation, particularly which mass is used in the formula. Clarification is sought on whether the radius mentioned refers to the orbital radius of Planet X compared to Planet V. The discussion emphasizes the importance of correctly applying gravitational formulas to determine orbital periods.
TheSerpent
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The Question
The Planet V has a year lasting 360 days. In the same star system is the Planet X. The Planet X has half the mass and triple the radius. A planet X year would be approximately _____ days
The attempt at a solution

Givens:
Tv= 360days
Tx= ?
mv = mv
mx = 1/2mv
rv = rv
rx = 3rvI derived a formula that incorporates time.
From which v = sqrt ( GM/r )
since T = 2pir / v

sub v into that formula and you get:

T = sqrt (4 pi^2 r^ 3 / GM )

with that I had two sets of values, Vulcan and X:
I plugged them into the formula and arranged for a common values such as Mv.
Then I subbed Mv from one formula into another.

This is what results:

8pi^23rv^3 / GTx^2 = 4pi^2rv^3/ GTv^2

through cancellations I ended up getting:

Tx = sqrt ( (2)(3)^3(360)^2 )
which was that amount of days.

Not sure if this method would be the correct way to go with this question or not.
 
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TheSerpent said:
The Question
The Planet V has a year lasting 360 days. In the same star system is the Planet X. The Planet X has half the mass and triple the radius. A planet X year would be approximately _____ days

The attempt at a solution

Givens:
TV= 360days
TX= ?
mV = mV
mX = 1/2mV
rV = rV
rX = 3rV

I derived a formula that incorporates time.
From which v = sqrt ( GM/r )
since T = 2(pi)r / v

sub v into that formula and you get:

T = sqrt (4 pi2 r3 / GM )

with that I had two sets of values, Vulcan and X:
I plugged them into the formula and arranged for a common values such as MV.
Then I subbed MV from one formula into another.

This is what results:

8pi23rv3 / GTx2 = 4pi2rv3/ GTv2

through cancellations I ended up getting:

TX = sqrt ( (2)(3)3(360)2 )
which was that amount of days.

Not sure if this method would be the correct way to go with this question or not.
Do you mean that the radius of the orbit of planet X is triple that of planet V ?

Does the mass of the planet matter? Is the M in the equation, v = sqrt ( GM/r ), the mass of the planet, or the mass of some other object?

Use the subscript, X2, & superscript, X2, buttons above the "Go Advanced" message box.
 
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