Shortest Distance in Euclidean Geometry: Proven or Definition?

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In Euclidean geometry, the shortest distance between a point and a line is the perpendicular distance. This can be demonstrated using the properties of right triangles, where the hypotenuse is always longer than either leg. The discussion highlights that the definition of a line influences whether this shortest distance can be proven or is merely a definition. The use of calculus of variations is suggested for proving the shortest distance as a function with a constant slope. Overall, the consensus is that the perpendicular distance is indeed the shortest.
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In euclidean geometry I believe the shortest distance is the perpendicular one. Can this be proven or is it a definition?
 
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Depends on your definition of a line. If it's a function with a constant slope, it can be proven with calculus of variations, I think. I don't think in Euclidian Geometry a line's rigorously defined.

EDIT: Never mind, I though you were asking if it could be proven that the shortest distance between two points is a line. See scurty's answer for a better reply
 
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aaaa202 said:
In euclidean geometry I believe the shortest distance is the perpendicular one. Can this be proven or is it a definition?

Not enough clarification here. Do you mean the shortest distance from a point not on a line to the line itself? I imagine it can be solved by considering the perpendicular line and another line emanating from the point. You will have a right triangle and the other line not perpendicular is the hypotenuse of the triangle, so therefore longer.
 
The length of the hypotenuse, c, of a right triangle, with legs a and b, satisfies c^2= a^2+ b^2 and so the hypotenuse is loner than either leg. Do you see why that means that the perpendicular line (one of the legs) is shorte than any othe line? (Ahh- that's essentially what scurty said.)
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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