Should pi be replaced with tau in mathematics?

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The discussion centers on the proposal to replace pi with tau in mathematics, with proponents arguing that tau simplifies formulas by relating to the radius rather than the diameter. Critics contend that pi is a well-established constant that effectively represents mathematical concepts, and changing notation could lead to confusion rather than clarity. Many participants emphasize that familiarity with pi makes it second nature for those who understand mathematics, while others argue that the transition to tau could enhance comprehension for learners. The debate also touches on the practicality of changing a long-standing convention, with some asserting that the benefits of switching to tau do not outweigh the potential disbenefits. Ultimately, the conversation highlights differing opinions on the impact of notation in mathematical education and practice.
  • #51
dimension10 said:
And that for pi cannot derive that for pi/2 algebraically so there is not best equation whatsoever.

I don't think you get the meaning of the word "better". "Better" does not mean "best". "Less" does not mean "the least". I never said that e^(i pi) = -1 was the "best" equation. I said it was "better" and gave "more" information than e^(i tau) = 1, something that's undeniably true.
 
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  • #52
Char. Limit said:
I don't think you get the meaning of the word "better". "Better" does not mean "best". "Less" does not mean "the least". I never said that e^(i pi) = -1 was the "best" equation. I said it was "better" and gave "more" information than e^(i tau) = 1, something that's undeniably true.

Yup, but there are an infinite number of equations better than that.

\exp(i \frac{\pi}{2})=i

\exp(i \frac{\pi}{4})=\frac{i+1}{\sqrt{2}}

\exp(i \frac{\pi}{8})=\sqrt{\frac{i+1}{\sqrt{2}}}
 
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  • #53
disregardthat said:
You can't derive Fermat's last theorem either, so what?

There does exist a proof for Fermat's last theorem. And here, I am saying that an infinite number of identities you cannot derive using {\exp}^{i}(\pi)=-1
 
  • #54
dimension10 said:
Yup, but there are an infinite number of equations better than that.

\exp(i \frac{\pi}{2})=i

\exp(i \frac{\pi}{4})=\frac{i+1}{\sqrt{2}}

\exp(i \frac{\pi}{8})=\sqrt{\frac{i+1}{\sqrt{2}}}

Okay, now I can see you're not even trying to dispute my argument. You're just making other arguments.
 
  • #56
I have to say I'm for using this; that said I wouldn't stop using pi, I'd use them together. In some cases it would be useful to define a constant that represents the ratio of radius to circumference, rather than diameter to circumference. In practice, it seem to me that radius is more fundamental than diameter: while we measure diameter, we use radius. I personally might start using that convention in my own work, as it keeps the constants from getting in the way. And it isn't like pi goes away, you just write that \tau = 2 \pi on your paper and everyone is on the same page as you. Also, I think 4\pi2 occurs a lot in formulas I've seen, so that just becomes \tau<sup>2</sup>. Also, if you integrated to get something squared, the constant should be 1/2. I'd rather use circumference = tau r and area = 1/2 tau r2 because I can tie that into my knowledge of integration and remember it better. Also, the existence of tau would make using radians even easier than it is now, because you could convert from a fraction of a circle to radians very intuitively by simply memorizing a few places of tau; using 6.3 is fairly accurate, comparable to 3.14. Trigonometric functions are the same, as the input they take is in radians anyways. This would make trigonometry so radically simple.
 
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