Show Light Has The Same Velocity in S and S'

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SUMMARY

The discussion focuses on the velocity transformation equations in the context of special relativity, specifically analyzing the components of a light ray's velocity in two frames, S and S'. The key equations used are u'_x = (u_x - v) / (1 - (v * u_x / c^2)) and u'_y = u_y / {gamma(1 - (v * u_x / c^2))}. The participant attempts to solve for u_x and u_y, concluding that u_x = v but is uncertain about the resulting value for u_y. The correct interpretation confirms that light maintains its speed c in both frames.

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  • Understanding of special relativity concepts, particularly Lorentz transformations
  • Familiarity with the speed of light as a constant (c)
  • Knowledge of the gamma factor in relativistic equations
  • Basic algebra skills for manipulating equations
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Homework Statement


Consider the velocity transformation equations. Find the x and y components of the velocity in the frame S of a light ray that has speed c along the y′axis of frame S′ where S and S′are the usual frames we have been considering with S′ moving with speed v with respect to S along the common x − x′ axes. Show that the light ray has speed c in the frame S.

Homework Equations


1. u'_x = (u_x-v)/{1-(v*u_x/c^2)}
2. u'_y = u_y/{gamma(1-(v*u_x/c^2))}
3. u'_z = u_z/{gamma(1-(v*u_x/c^2))}

The Attempt at a Solution


u_z = u'_z = 0, obviously. I'm looking for u_x and u_y, so I need to start with u_x. I set u'_x to 0 and solved, getting u_x = v. I'm not sure if that's right, or if I should've gotten c, but I tried to plug u_x = v into equation 2, and did not get that u_y was c.
 
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Think about how to get speed from the x and y components of velocity.
 

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